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The moment of inertia of a uniform circular disc about a tangent in its own plane is 5/4MR2 where M is the mass and R is the radius of the disc. Find its moment of inertia about an axis

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प्रश्न

The moment of inertia of a uniform circular disc about a tangent in its own plane is 5/4MR2 where M is the mass and R is the radius of the disc. Find its moment of inertia about an axis through its centre and perpendicular to its plane. 

योग
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उत्तर

  1. M.I. of a uniform circular disc about a tangent in its own plane, I1 = `5/4`MR 
  2. Applying parallel axis theorem 
    I1 = I2 + Mh
    ∴ I2 = I1 – MR2 = `5/4`MR2 - MR2 = `("MR"^2)/4` 
  3. Applying perpendicular axis theorem,
    I3 = I2 + I2 = 2I2
    ∴ I3 = `2 xx ("MR"^2)/4 = ("MR"^2)/2`  
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