Question

The molar conductivity at infinite dilution for `λ_(H^+)^∞ = 348.65  S  cm^2  mol^(−1)` and for `λ_(CH_3COO^-)^∞ = 41.4  S  cm^2  mol^(−1)` respectively.

Calculate the degree of dissociation (α) of acetic acid if its molar conductivity `∧_m^c  is  40.65  S  cm^2  mol^(−1)`.

Answer 1

Given: `λ_(H^+)^∞ = 348.65  S  cm^2  mol^(−1)`

`λ_(CH_3COO^-)^∞ = 41.4  S  cm^2  mol^(−1)`

`∧_m^c = 40.65  S  cm^2  mol^(−1)`

Formula: `∧_((CH_3COOH))^∞ = λ_(H^+)^∞ + λ_(CH_3COO^-)^∞`

= 348.65 + 41.4

`∧_m^∞ = 390.05  S  cm^2  mol^(−1)`

Degree of dissociation (α) = `(∧_m^c)/(∧_m^∞)`

= `40.65/390.05`

= 0.1042

= 10.42 %