Question

The molar conductivity at infinite dilution for `λ_(H^+)^∞` = 348.65 S cm² mol⁻¹ and for `λ_(CH_3COO^-)^∞` = 41.4 S cm² mol⁻¹ respectively.

Calculate the degree of dissociation (α) of acetic acid if its molar conductivity `∧_m^c` is 40.65 S cm² mol⁻¹.

Answer 1

Given: `λ_(H^+)^∞` = 348.65 S cm² mol⁻¹

`λ_(CH_3COO^-)^∞` = 41.4 S cm² mol⁻¹

`∧_m^c` = 40.65 S cm² mol⁻¹

Formula: `∧_((CH_3COOH))^∞ = λ_(H^+)^∞ + λ_(CH_3COO^-)^∞`

= 348.65 + 41.4

`∧_m^∞` = 390.05 S cm² mol⁻¹

Degree of dissociation (α) = `(∧_m^c)/(∧_m^∞)`

= `40.65/390.05`

= 0.1042

= 10.42 %