Question

The molar conductivities at infinite dilution of barium chloride, sulphuric acid and hydrochloric acid are 280, 860 and 426 S cm² mol⁻¹ respectively. The molar conductivity at infinite dilution of barium sulphate is ______ S cm² mol⁻¹.

(Round off to the nearest integer)

Answer 1

The molar conductivities at infinite dilution of barium chloride, sulphuric acid and hydrochloric acid are 280, 860 and 426 S cm² mol⁻¹ respectively. The molar conductivity at infinite dilution of barium sulphate is 288 S cm² mol⁻¹.

Explanation:

Given:

\[\ce{\Lambda{^0_m}}\] ​(BaCl₂) = 280 S cm² mol⁻¹

\[\ce{\Lambda{^0_m}}\] (H₂SO₄) = 860 S cm² mol⁻¹

\[\ce{\Lambda{^0_m}}\] (HCl) = 426 S cm² mol⁻¹

To find:

\[\ce{\Lambda{^0_m}}\] (BaSO₄) = ?

Formula:

\[\ce{\Lambda{^0_m}(BaSO_4) = \Lambda{^0_m}(BaCl_2) + \Lambda{^0_m}(H_2SO_4) - 2\Lambda{^0_m}(HCl)}\]

= 280 + 860 − 2 × 426

= 280 + 860 − 852

= 288 S cm² mol⁻¹

∴ The molar conductivity at infinite dilution of barium sulphate is 288 S cm² mol⁻¹.