Advertisements
Advertisements
प्रश्न
The mean of 100 observations is 40. It is found that an observation 53 was misread as 83.
Find the correct mean.
Advertisements
उत्तर
Given the mean of 100 observations is 40.
`(sumx)/n = barx`
⇒ `(sumx)/n = 40`
⇒ x = 40 x 100
⇒ x = 4000
Incorrect value of x = 4000
Correct value of x = Incorrect value of x - Incorrect observation + correct observation
= 4000 - 83 + 53
= 3970
Correct mean = `("correct value of" sumx)/n`
= `3970/100`
= 39.7
APPEARS IN
संबंधित प्रश्न
Find the mean of 43, 51, 50, 57 and 54.
Find the mean of the first six natural numbers.
Find the mean of the first ten odd natural numbers.
Find x if 9, x, 14, 18 x, x, 8, 10 and 4 have a mean of 11.
The mean of 200 items was 50. Later on, it was discovered that two items were misread as 92 and 8 instead of 192 and 88.
Find the correct mean.
If different values of variable x are 9.8, 5.4, 3.7, 1.7, 1.8, 2.6, 2.8, 8.6, 10.5 and 11.1;
find
(i) the mean ` barx `
(ii) the value of ` sum (x_i - barx)`
The mean of 5 numbers is 18. If one number is excluded, the mean of the remaining number becomes 16. Find the excluded number.
Find the mean of 8, 12, 16, 22, 10 and 4. Find the resulting mean, if the observations, given above, be: divided by 2.
The mean of 16 numbers is 8. If 2 is added to every number, what will be the new mean?
If `bar"X"` is the mean of n observations x1, x2, x3,..., xn then the mean of `x_1/"a", x_2/"a", x_3/"a",...,x_"n"/"a" "is" bar"X"/"a"`, where a is an non-zero number.
i.e., if each observation is divided by a non-zero number, then the mean is also divided by it.
