Advertisements
Advertisements
प्रश्न
The marks of 200 students in a test were recorded as follows:
| Marks % |
0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | 70 - 80 | 80 - 90 | 90 - 100 |
| No. of students |
5 | 7 | 11 | 20 | 40 | 52 | 36 | 15 | 9 | 5 |
Using graph sheet draw ogive for the given data and use it to find the,
- median,
- number of students who obtained more than 65% marks
- number of students who did not pass, if the pass percentage was 35.
आलेख
योग
Advertisements
उत्तर
| Marks (%) | f | cf |
| 0 - 10 | 5 | 5 |
| 10 - 20 | 7 | 12 |
| 20 - 30 | 11 | 23 |
| 30 - 40 | 20 | 43 |
| 40 - 50 | 40 | 83 |
| 50 - 60 | 52 | 135 |
| 60 - 70 | 36 | 171 |
| 70 - 80 | 15 | 186 |
| 80 - 90 | 9 | 195 |
| 90 - 100 | 5 | 200 |
a. Median = `50+ ((100-83)/52xx10)`
`50+(17/52xx10)`
Median = 53.27%
b. 65% lies in the 60–70% class.
From the cumulative frequency table:
Students scoring < 60% = 135
Students scoring < 70% = 171
Approximate number scoring ≤ 65 = `135+(5/10 xx 36)`
= 135 + 18
= 153
⇒ Students scoring > 65 = 200 – 153 = 47 students
c. 35% lies in 30–40% class:
Students scoring < 30% = 23
35 is halfway between 30 and 40:
⇒ Total not passing = 23 + 10 = 33 students

shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
