हिंदी

The marks of 200 students in a test were recorded as follows: Marks% 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90-100 No. of students 5 7 11 20 40 52 36 15 9 5 - Mathematics

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प्रश्न

The marks of 200 students in a test were recorded as follows:

Marks
%
0 - 10 10 - 20 20 - 30  30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 80 - 90 90 - 100
No. of
students
5 7 11 20 40 52 36 15 9 5

Using graph sheet draw ogive for the given data and use it to find the,

  1. median,
  2. number of students who obtained more than 65% marks
  3. number of students who did not pass, if the pass percentage was 35.
आलेख
योग
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उत्तर

Marks (%) f cf
0 - 10 5 5
10 - 20 7 12
20 - 30 11 23
30 - 40 20 43
40 - 50 40 83
50 - 60 52 135
60 - 70 36 171
70 - 80 15 186
80 - 90 9 195
90 - 100 5 200

a. Median = `50+ ((100-83)/52xx10)`

`50+(17/52xx10)`

Median = 53.27%

b. 65% lies in the 60–70% class.

From the cumulative frequency table:

Students scoring < 60% = 135

Students scoring < 70% = 171

Approximate number scoring ≤ 65 = `135+(5/10 xx 36)`

= 135 + 18

= 153

⇒ Students scoring > 65 = 200 – 153 = 47 students

c. 35% lies in 30–40% class:

Students scoring < 30% = 23

35 is halfway between 30 and 40:

⇒ Total not passing = 23 + 10 = 33 students

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