हिंदी

The magnifying power of an astronomical telescope in normal adjustment is 2.9 and the objective and the eyepiece are separated by a distance of 150 cm. Find the focal lengths of the two lenses.

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प्रश्न

The magnifying power of an astronomical telescope in normal adjustment is 2.9 and the objective and the eyepiece are separated by a distance of 150 cm. Find the focal lengths of the two lenses.

संख्यात्मक
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उत्तर

Given: D = 150 cm, m = 2.9

fo = ?

Since, `m = f_o/f_e`

D = `f_o + f_e`

`2.9 = f_o/f_e`

`f_o = f_e xx 2.9` .....(i)

`f_o + f_e = 150` cm

From equation (i),

`2.9 f_e + f_e = 150`

`3.9f_e = 150`

fe = 38.46 cm

fo = 2.9 × 38.46

fo = 111.54 cm

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2022-2023 (March) Delhi Set 1

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