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The lines represented by 4x + 3y = 9 and px – 6y + 3 = 0 are parallel. Find the value of p. - Mathematics

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प्रश्न

The lines represented by 4x + 3y = 9 and px – 6y + 3 = 0 are parallel. Find the value of p.

योग
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उत्तर

Writing the given lines 4x + 3y = 9

And px – 6y + 3 = 0 in the form of y = mx + c

4x + 3y = 9

`=>` 3y = −4x + 9

`y = (-4)/3x + 9/3`

`=> y = (-4)/3x + 3`   ...(i)

Here, m1 = slope = `(-4)/3`

And px – 6y + 3 = 0

`=>` –6y = –px – 3

`y = (-p)/(-6)x - 3/(-6)`

= `p/6x + 1/2`

`=> y = p/6x + 1/2`   ...(ii)

Here, slope m2 = `p/6`

∵ Lines are parallel

∴ Their slopes are equal i.e., m1 = m2

∴ `p/6 = (-4)/3`

`=>` 3p = –24

`p = (-24)/3`

p = –8

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