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प्रश्न
The line through P(5, 3) intersects y-axis at Q.
- Write the slope of the line.
- Write the equation of the line.
- Find the co-ordinates of Q.

योग
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उत्तर
i. The equation of the y-axis is x = 0
Given that the required line through P(5, 3)
Intersects the y-axis at Q and the angle of inclination is 45°
Therefore slope of the line PQ = tan 45° = 1
ii. The equation of a line passing through the point
A(x1, y1) with slope ‘m’ is
y – y1 = m(x – x1)
Therefore, the equation of the line passing through the point P(5, 3) with slope 1 is
y – 3 = 1 × (x – 5)
`=>` y – 3 = x – 5
`=>` x – y = 2
iii. From subpart (ii), the equation of the line PQ
Is x – y = 2
Given that the line intersects with the y-axis, x = 0
Thus, substituting x = 0 in the equation x – y = 2
We have, 0 – y = 2
`=>` y = −2
Thus, the coordinates point of intersection Q are q(0, −2)
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