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The Interior of a Building is in the Form of a Cylinder of Base Radius 12 M and Height 3.5 M, Surmounted by a Cone of Equal Base and Slant Height 12.5 M. Find the Internal Curved - Mathematics

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प्रश्न

The interior of a building is in the form of a cylinder of base radius 12 m and height 3.5 m, surmounted by a cone of equal base and slant height 12.5 m. Find the internal curved surface area and the capacity of the building.

संक्षेप में उत्तर
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उत्तर

Height of the cone

`=sqrt((12.5)^2 - (12)^2)`

`=sqrt(12.25)`

`= 3.5m`

Capacity (volume) of cone

`=1/3 pir^2h`

`=1/3 xx 22/7 xx 12 xx 3.5`

`=528 m^3`

Capacity (volume) of cylinder

`=pir^2 h`

`=22/7 xx 12xx 12 xx 3.5`

`=1584 m^3`

Therefore,

Total capacity of building

`= 1584 + 528`

`=2112 m^3`

Internal curved surface area of the building

`=2pirh + pirl`

`= pir(2h+l)`

`=22/7 xx 12 (2 xx 3.5 + 12.5)`

`=22/7 xx 12 xx 19.5`

`=735.43m^2`

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अध्याय 14: Surface Areas and Volumes - Exercise 14.3 [पृष्ठ ८३]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 14 Surface Areas and Volumes
Exercise 14.3 | Q 52 | पृष्ठ ८३
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