हिंदी

The Integrating Factor of the differential equation dydx-y=2x2 is ______. - Mathematics

Advertisements
Advertisements

प्रश्न

The Integrating Factor of the differential equation `dy/dx - y = 2x^2` is ______.

विकल्प

  • e-x

  • e-y

  • `1/x`

  • x

MCQ
रिक्त स्थान भरें
Advertisements

उत्तर

The Integrating Factor of the differential equation `dy/dx - y = 2x^2` is `underline(1/x)`

Explanation:

The differential equation is

`x dy/dx - y = 2x^2`

or `dy/dx - 1/x y = 2x`

Here `P = - 1/x, Q = 2x`

∴ `∫ P  dx =int - 1/x` dx

=` - log x = log  1/x`

⇒ `I.F. = e^(int P dx)`

`= e^(log 1//x) = 1/x`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Equations - Exercise 9.6 [पृष्ठ ४१४]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 9 Differential Equations
Exercise 9.6 | Q 18 | पृष्ठ ४१४

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the the differential equation for all the straight lines, which are at a unit distance from the origin.


For the differential equation, find the general solution:

`cos^2 x dy/dx + y = tan x(0 <= x < pi/2)`


For the differential equation, find the general solution:

`x log x dy/dx + y=    2/x log x`


For the differential equation, find the general solution:

`x dy/dx + y - x + xy cot x = 0(x != 0)`


For the differential equation given, find a particular solution satisfying the given condition:

`(1 + x^2)dy/dx + 2xy = 1/(1 + x^2); y = 0`  when x = 1


For the differential equation given, find a particular solution satisfying the given condition:

`dy/dx - 3ycotx = sin 2x; y = 2`  when `x = pi/2`


Find the equation of a curve passing through the point (0, 2) given that the sum of the coordinates of any point on the curve exceeds the magnitude of the slope of the tangent to the curve at that point by 5.


Solve the differential equation `(tan^(-1) x- y) dx = (1 + x^2) dy`


Solve the differential equation `x dy/dx + y = x cos x + sin x`,  given that y = 1 when `x = pi/2`


\[\left( 1 + x^2 \right)\frac{dy}{dx} + y = e^{tan^{- 1} x}\]

dx + xdy = e−y sec2 y dy


\[\frac{dy}{dx}\] + y cos x = sin x cos x


\[\left( x^2 - 1 \right)\frac{dy}{dx} + 2\left( x + 2 \right)y = 2\left( x + 1 \right)\]

\[\frac{dy}{dx} - y = x e^x\]

Solve the following differential equation:- \[\left( \cot^{- 1} y + x \right) dy = \left( 1 + y^2 \right) dx\]


Find the integerating factor of the differential equation `xdy/dx - 2y = 2x^2` . 


Solve the differential equation: (1 +x) dy + 2xy dx = cot x dx 


If f(x) = x + 1, find `"d"/"dx"("fof") ("x")`


Solve the differential equation: `(1 + x^2) dy/dx + 2xy - 4x^2 = 0,` subject to the initial condition y(0) = 0.


Solve the following differential equation:

`("x" + 2"y"^3) "dy"/"dx" = "y"`


Solve the following differential equation:

y dx + (x - y2) dy = 0


Find the general solution of the equation `("d"y)/("d"x) - y` = 2x.

Solution: The equation `("d"y)/("d"x) - y` = 2x

is of the form `("d"y)/("d"x) + "P"y` = Q

where P = `square` and Q = `square`

∴ I.F. = `"e"^(int-"d"x)` = e–x

∴ the solution of the linear differential equation is

ye–x = `int 2x*"e"^-x  "d"x + "c"`

∴ ye–x  = `2int x*"e"^-x  "d"x + "c"`

= `2{x int"e"^-x "d"x - int square  "d"x* "d"/("d"x) square"d"x} + "c"`

= `2{x ("e"^-x)/(-1) - int ("e"^-x)/(-1)*1"d"x} + "c"`

∴ ye–x = `-2x*"e"^-x + 2int"e"^-x "d"x + "c"`

∴ e–xy = `-2x*"e"^-x+ 2 square + "c"`

∴ `y + square + square` = cex is the required general solution of the given differential equation


Which of the following is a second order differential equation?


Integrating factor of the differential equation `(1 - x^2) ("d"y)/("d"x) - xy` = 1 is ______.


The solution of `(1 + x^2) ("d"y)/("d"x) + 2xy - 4x^2` = 0 is ______.


The equation x2 + yx2 + x + y = 0 represents


The integrating factor of differential equation `(1 - y)^2  (dx)/(dy) + yx = ay(-1 < y < 1)`


State whether the following statement is true or false.

The integrating factor of the differential equation `(dy)/(dx) + y/x` = x3 is – x.


If y = y(x) is the solution of the differential equation, `(dy)/(dx) + 2ytanx = sinx, y(π/3)` = 0, then the maximum value of the function y (x) over R is equal to ______.


If sin x is the integrating factor (IF) of the linear differential equation `dy/dx + Py` = Q then P is ______.


Find the general solution of the differential equation:

`(x^2 + 1) dy/dx + 2xy = sqrt(x^2 + 4)`


Solve the differential equation `dy/dx+2xy=x` by completing the following activity.

Solution: `dy/dx+2xy=x`       ...(1)

This is the linear differential equation of the form `dy/dx +Py =Q,"where"`

`P=square` and Q = x

∴ `I.F. = e^(intPdx)=square`

The solution of (1) is given by

`y.(I.F.)=intQ(I.F.)dx+c=intsquare  dx+c`

∴ `ye^(x^2) = square`

This is the general solution.


If sec x + tan x is the integrating factor of `dy/dx + Py` = Q, then value of P is ______.


The slope of tangent at any point on the curve is 3. lf the curve passes through (1, 1), then the equation of curve is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×