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The Figure below shows a ray of monochromatic light LM incident on the first surface AB of a regular (equilateral) glass prism ABC. The emergent ray grazes the adjacent surface AC. - Physics (Theory)

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प्रश्न

The Figure below shows a ray of monochromatic light LM incident on the first surface AB of a regular (equilateral) glass prism ABC. The emergent ray grazes the adjacent surface AC. Calculate the angle of incidence. (Refractive Index of glass = 1.5)

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उत्तर

Given A = 60°, n = 1.5, At the surface AC, r2 is the critical angle

`sin r_2 = 1/n`

= `1/1.5`

= `2/3`

= 0.6667

∴ r2 = sin-1 (0.6667)

= 41.8°

Also, r1 + r2 = A

r1 = A - r2

= 60° - 41.8°

= 18.2°

At the surface AB,

`sini/(sinr_1) = n`

sin i = 1.5 × sin 18.2°

= 1.5 × 0.31

= 0.465

∴ i = sin-1 (0.465)

= 27.7°

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Refraction of Monochromatic Light
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