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प्रश्न
The equation of circle whose diameter lies on 3x + 5y = -7 and 2x - y = 4 which passes through `(-5, 1/2)` is
विकल्प
x2 + y2 - 2x + 4y = 149
x2 + y2 - 2x + 4y = `149/4`
x2 + y2 + 2x - 4y = 149
x2 + y2 + 2x - 4y = `149/4`
MCQ
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उत्तर
x2 + y2 - 2x + 4y = `149/4`
Explanation:
Since the centre always lies on the diameter, Solving 3x +Sy= -7 and 2x - y = 4, we get Co-ordinates of the centre = (1, -2).
The circle passes through `(-5, 1/2)`
∴ `"r"^2 = (1 + 5)^2 + (- 2 - 1/2)^2`
`= 36 + 25/4 = 169/4`
∴ Equation of circle is
(x - 1)2 + (y + 2)2 = `169/4`
⇒ x2 + y2 - 2x + 4y = `149/4`
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Equation of a Circle in Different Forms
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