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The difference between the outer and inner curved surface area of a hollow cylinder is 264 cm2. If its height is 14 cm and the volume of the material in it is 1980 cm3, find its total surface area. - Mathematics

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प्रश्न

The difference between the outer and inner curved surface area of a hollow cylinder is 264 cm2. If its height is 14 cm and the volume of the material in it is 1980 cm3, find its total surface area.

योग
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उत्तर

Curved surface area of cylinder = πr2h
Height h = 14cm
The difference between the outer and inner curved surface area = 264cm2
2π x {(Router)-(Rin)} x h = 264cm2
⇒ π x {(Router)-(Rin)} x h = 132     ...(1)
Volume of material in cylinder = 1980cm3
π{(Router)2-(Rin)2} x h = 1980
π{(Rouer)-(Rin){(Router+(Rin)} x h = 1980   ...(2)
Substituting (1) in (2), we get
{(Router+(Rin)} x 132 = 1980
∴ {(Router+Rin)} = 15cm
Total surface area of a hollow cylinder
= 2π{(Router+Rin)} x h + 2π{(Router)2-(Rin)2}

= `2pi xx 15 xx 14 + 2 xx (1980)/(14)`
= 1602cm2
∴ The total surface area of the hollow cylinder is 1602cm2.

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अध्याय 25: Surface Areas and Volume of Solids - Exercise 25.2

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 25 Surface Areas and Volume of Solids
Exercise 25.2 | Q 29
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