Advertisements
Advertisements
प्रश्न
The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If ∠DAC = 32º and ∠AOB = 70º, then ∠DBC is equal to ______.
विकल्प
24º
86º
38º
32º
Advertisements
उत्तर
The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If ∠DAC = 32º and ∠AOB = 70º, then ∠DBC is equal to 38º.
Explanation:
Given: ∠AOB = 70°
∠DAC = 32°
∵ AD || BC and AC is transversal
∴ ∠ACB = 32°
Now, ∠AOB + ∠BOC = 180°
⇒ 70° + ∠BOC = 180°
⇒ ∠BOC = 180° – 70°
⇒ ∠BOC = 110°
Sum of all angles of a triangle = 180°
⇒ ∠BOC + ∠BCO + ∠OBC = 180°
⇒ 110° + 32° + ∠OBC = 180°
⇒ 142° + ∠OBC = 180°
⇒ ∠OBC = 180° – 142°
⇒ ∠OBC = 38°
Hence, ∠DBC = 38°
APPEARS IN
संबंधित प्रश्न

Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ (Figure). Show that AC and PQ bisect each other.

In a parallelogram ABCD, AB = 10 cm and AD = 6 cm. The bisector of ∠A meets DC in E. AE and BC produced meet at F. Find the length of CF.
A diagonal of a parallelogram bisects one of its angles. Show that it is a rhombus.
P and Q are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. Show that PQ is bisected at O.
ABCD is a rectangle in which diagonal BD bisects ∠B. Show that ABCD is a square.
P is the mid-point of the side CD of a parallelogram ABCD. A line through C parallel to PA intersects AB at Q and DA produced at R. Prove that DA = AR and CQ = QR.
If diagonals of a quadrilateral bisect each other, it must be a parallelogram.
Two sticks each of length 5 cm are crossing each other such that they bisect each other. What shape is formed by joining their endpoints? Give reason.
Two sticks each of length 7 cm are crossing each other such that they bisect each other at right angles. What shape is formed by joining their end points? Give reason.
