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The determinant babbcbcacabaabbabbcaccaaba|b2-abb-cbc-acab-a2a-bb2-abbc-acc-aab-a2| equals ______. - Mathematics

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प्रश्न

The determinant `|("b"^2 - "ab", "b" - "c", "bc" - "ac"),("ab" - "a"^2, "a" - "b", "b"^2 - "ab"),("bc" - "ac", "c" - "a", "ab" - "a"^2)|` equals ______.

विकल्प

  • abc (b–c) (c – a) (a – b)

  • (b–c) (c – a) (a – b)

  • (a + b + c) (b – c) (c – a) (a – b)

  • None of these

MCQ
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उत्तर

The determinant `|("b"^2 - "ab", "b" - "c", "bc" - "ac"),("ab" - "a"^2, "a" - "b", "b"^2 - "ab"),("bc" - "ac", "c" - "a", "ab" - "a"^2)|` equals none of these.

Explanation:

We have, `|("b"^2 - "ab", "b" - "c", "bc" - "ac"),("ab" - "a"^2, "a" - "b", "b"^2 - "ab"),("bc" - "ac", "c" - "a", "ab" - "a"^2)|` 

= `|("b"("b" - "a"), "b" - "c", "c"("b" - "a")),("a"("b" - "a"), "a" - "b", "b"("b" - "a")),("c"("b" - "a"), "c" - "a", "a"("b" - "a"))|`

[Taking (b – a) common from C1 and C3 each]

= `("b" - "a")^2 |("b", "b" - "c", "c"),("a", "a" - "b", "b"),("c", "c" - "a", "a")|`

[Applying C2 → C2 + C3]

= `("b" - "a")^2 |("b", "b", "c"),("a", "a", "b"),("c", "c", "a")|`

= 0  .....[As C1 and C2 are identical]

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अध्याय 4: Determinants - Exercise [पृष्ठ ८०]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 4 Determinants
Exercise | Q 27 | पृष्ठ ८०

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