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प्रश्न
The derivative of `cos^-1 (2x^2 - 1)` w.r.t `cos^-1 x` is ______
विकल्प
2
`(-1)/(2sqrt(1 - x^2))`
`2/x`
1 - x2
MCQ
रिक्त स्थान भरें
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उत्तर
The derivative of `cos^-1 (2x^2 - 1)` w.r.t `cos^-1 x` is 2.
Explanation:
Let u = `cos^-1 (2x^2 - 1)` and v = `cos^-1 x`
Putting x = cosθ in both equations, we get
u = `cos^-1(2cos^2theta - 1)`
u = `cos^-1(cos2theta)`
= 2θ
v = `cos^-1(cosθ)`
= θ
∴ `(du)/(d theta) = 2 "and" (dv)/(d theta) = 1`
∴ `(du)/(dv) = (((du)/(d theta)))/(((dv)/(d theta)))` = 2
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Derivative of Inverse Functions
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