Advertisements
Advertisements
प्रश्न
The denominator of a fraction exceeds Its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, we get `3/2`. Find the original fraction.
Advertisements
उत्तर
Let the numerator & denominator be ‘n’ & ‘d’
Given that denominator exceeds numerator by 8
∴ d = n + 8 ...(1)
If numerator increased by 17 & denominator decreased by 1,
it becomes (n + 17) & (d – 1), fraction is `3/2`
i.e `("n" + 17)/("d" - 1) = 3/2` by cross multiplying, we get
`("n" + 17)/("d" - 1) = 3/2`
2(n + 17) = 3(d – 1)
2n + 2 × 17 = 3d – 3
∴ 34 + 3 = 3d – 2n
∴ 3d – 2n = 37 ...(2)
Substituting equation (1) in (2), we get,
3 × (n + 8) – 2n = 37
3n + 3 × 8 – 2n = 37
∴ n = 37 – 24 = 13
d = n + 8 = 13 + 8 = 21
The fraction is `"n"/"d" = 13/21`
APPEARS IN
संबंधित प्रश्न
Divide the given polynomial by the given monomial.
8(x3y2z2 + x2y3z2 + x2y2z3) ÷ 4x2y2z2
Write the degree of each of the following polynomials.
Write each of the following polynomials in the standard form. Also, write their degree.
a2 + 4 + 5a6
Divide x + 2x2 + 3x4 − x5 by 2x.
Divide 3x3y2 + 2x2y + 15xy by 3xy.
Divide 14x2 − 53x + 45 by 7x − 9.
Divide −21 + 71x − 31x2 − 24x3 by 3 − 8x.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 34x − 22x3 − 12x4 − 10x2 − 75 | 3x + 7 |
Find whether the first polynomial is a factor of the second.
4y + 1, 8y2 − 2y + 1
Divide 24(x2yz + xy2z + xyz2) by 8xyz using both the methods.
