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प्रश्न
The curved surface area of a cylindrical pillar is 264 m2 and its volume is 924 m3. Find the diameter and the height of the pillar.
योग
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उत्तर
Here, r m= radius of the cylinder
h m= height of the cylinder
Curved surface area of the cylinder = 2πrh ... (1)
Volume of the cylinder = πr2h ... (2)
924 = πr2h
\[h = \frac{924}{\pi r^2}\]
Then, substitute h into equation (1):
264 = 2πrh
\[264 = 2\pi r\left( \frac{924}{\pi r^2} \right)\]
264r = 2(924)
r = 7 m, so d = 14 m
Then, substitute h into equation (1):
264 = 2πrh
\[264 = 2\pi r\left( \frac{924}{\pi r^2} \right)\]
264r = 2(924)
\[r = \frac{2 \times 924}{264}\]
\[h = \frac{924}{\pi r^2}\]
h = \[\frac{924}{\frac{22}{7} \times 7^2} = 6 m\]
h = \[\frac{924}{\frac{22}{7} \times 7^2} = 6 m\]
Hence, the diameter and the height of the cylinder are 14 m and 6 m, respectively.
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