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The co-ordinates of the centroid of a triangle are (2, −5). If two of its vertices are (−6, 5) and (11, 8), find the coordinates of the third vertex. - Mathematics

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प्रश्न

The co-ordinates of the centroid of a triangle are (2, −5). If two of its vertices are (−6, 5) and (11, 8), find the coordinates of the third vertex.

योग
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उत्तर

The formula used is the centroid (intersection of the medians) of triangle ABC:

G = `((x_1 + x_2 + x_3) / 3, (y_1 + y_2 + y_3) / 3),`

Because the centroid divides each median in the ratio 2 : 1,

To find the missing vertex (x3,y3) when G and the other two vertices (x1,y1), (x2,y2) are known,

x3 = 3Gx − x1 − x2,

y3 = 3Gy − y1 − y2

Applying this to G = (2, −5), A = (−6, 5), B = (11, 8):

⇒ x3 = 3 × 2 − (−6) − 11

= 6 + 6 − 11

∴ x3 = 1

⇒ y3 = 3 × (−5) − 5 − 8

= −15 − 13

∴ y3 = −28

Hence, the third vertex is (1, −28).

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अध्याय 11: Section formula - Exercise 11A [पृष्ठ २२९]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 11 Section formula
Exercise 11A | Q 24. | पृष्ठ २२९
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