Question

The circumference of a circle is 22 cm. Find the area of its quadrant. 

Answer 1

Let the radius of the circle be r.

Now, 

Circumference = 22

⇒ 2πr = 22

`⇒ r = (22xx7)/44 = 7/2 "cm"`

Now, Area of quadrant `=1/4pi"r"^2=1/4xx22/7xx(7/2)^2=77/8 "cm"^2`

Hence, the area of the quadrant of the circle is `77/8 "cm"^2`.