हिंदी

The area of the region bounded by parabola y2 = x and the straight line 2y = x is ______. - Mathematics

Advertisements
Advertisements

प्रश्न

The area of the region bounded by parabola y2 = x and the straight line 2y = x is ______.

विकल्प

  • `4/3`sq.units

  • 1 sq.units

  • `2/3`sq.units

  • `1/3`sq.units

MCQ
रिक्त स्थान भरें
Advertisements

उत्तर

The area of the region bounded by parabola y2 = x and the straight line 2y = x is `4/3`sq.units.

Explanation:

Given equation of parabola is y2 = x   ......(i)

And equation of straight line is 2y = x  ......(ii)

Solving equation (i) and (ii)

We get `(x/2)^2` = x

⇒ `x^2/4` = x

⇒ x2 = 4x

⇒ x(x – 4) = 0

∴ x = 0, 4

Required area = `int_0^4 sqrt(x)  "d"x - int_0^4  x/2  "d"x`

= `2/3 [x^(3/2)]_0^4 - 1/2 * 1/2 [x^2]_0^4`

= `2/3 [(4)^(3/2) - 0] - 1/4 [(4)^2 - 0]`

= `2/3 xx 8 - 1/4 xx 16`

= `16/3 - 4`

= `4/3` sq.units

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Application Of Integrals - Exercise [पृष्ठ १७८]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 8 Application Of Integrals
Exercise | Q 29 | पृष्ठ १७८

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the area bounded by the curve y2 = 4axx-axis and the lines x = 0 and x = a.


Find the area of the sector of a circle bounded by the circle x2 + y2 = 16 and the line y = x in the ftrst quadrant.


Using integration, find the area of the region bounded between the line x = 2 and the parabola y2 = 8x.


Find the area of the region bounded by the curve xy − 3x − 2y − 10 = 0, x-axis and the lines x = 3, x = 4.


Find the area enclosed by the curve x = 3cost, y = 2sin t.


Find the area of the region \[\left\{ \left( x, y \right): \frac{x^2}{a^2} + \frac{y^2}{b^2} \leq 1 \leq \frac{x}{a} + \frac{y}{b} \right\}\]


Find the area of the region between the circles x2 + y2 = 4 and (x − 2)2 + y2 = 4.


Find the area of the region bounded by \[y = \sqrt{x}, x = 2y + 3\]  in the first quadrant and x-axis.


Find the area, lying above x-axis and included between the circle x2 + y2 = 8x and the parabola y2 = 4x.


Find the area of the region bounded by \[y = \sqrt{x}\] and y = x.


Find the area enclosed by the curve \[y = - x^2\] and the straight line x + y + 2 = 0. 


Find the area of the region bounded by y = | x − 1 | and y = 1.


Find the area of the circle x2 + y2 = 16 which is exterior to the parabola y2 = 6x.


Using integration, find the area of the following region: \[\left\{ \left( x, y \right) : \frac{x^2}{9} + \frac{y^2}{4} \leq 1 \leq \frac{x}{3} + \frac{y}{2} \right\}\]


Find the area enclosed by the curves 3x2 + 5y = 32 and y = | x − 2 |.


If the area bounded by the parabola \[y^2 = 4ax\] and the line y = mx is \[\frac{a^2}{12}\] sq. units, then using integration, find the value of m. 

 


The ratio of the areas between the curves y = cos x and y = cos 2x and x-axis from x = 0 to x = π/3 is ________ .


Using integration, find the area of the smaller region bounded by the ellipse `"x"^2/9+"y"^2/4=1`and the line `"x"/3+"y"/2=1.`


The area of the region bounded by the curve x = y2, y-axis and the line y = 3 and y = 4 is ______.


Find the area of the region bounded by the curve y2 = 4x, x2 = 4y.


Find the area of region bounded by the triangle whose vertices are (–1, 1), (0, 5) and (3, 2), using integration.


Draw a rough sketch of the region {(x, y) : y2 ≤ 6ax and x 2 + y2 ≤ 16a2}. Also find the area of the region sketched using method of integration.


Draw a rough sketch of the given curve y = 1 + |x +1|, x = –3, x = 3, y = 0 and find the area of the region bounded by them, using integration.


Area of the region bounded by the curve y = cosx between x = 0 and x = π is ______.


The area of the region bounded by the ellipse `x^2/25 + y^2/16` = 1 is ______.


The curve x = t2 + t + 1,y = t2 – t + 1 represents


If a and c are positive real numbers and the ellipse `x^2/(4c^2) + y^2/c^2` = 1 has four distinct points in common with the circle `x^2 + y^2 = 9a^2`, then


Area lying in the first quadrant and bounded by the circle `x^2 + y^2 = 4` and the lines `x + 0` and `x = 2`.


Area of the region bounded by the curve `y^2 = 4x`, `y`-axis and the line `y` = 3 is:


Find the area of the region bounded by the curve `y^2 - x` and the line `x` = 1, `x` = 4 and the `x`-axis.


Find the area of the region bounded by `x^2 = 4y, y = 2, y = 4`, and the `y`-axis in the first quadrant.


The area bounded by the curve `y = x|x|`, `x`-axis and the ordinate `x` = – 1 and `x` = 1 is given by


The area bounded by `y`-axis, `y = cosx` and `y = sinx, 0  ≤ x - (<pi)/2` is


Make a rough sketch of the region {(x, y): 0 ≤ y ≤ x2, 0 ≤ y ≤ x, 0 ≤ x ≤ 2} and find the area of the region using integration.


Find the area of the region enclosed by the curves y2 = x, x = `1/4`, y = 0 and x = 1, using integration.


Let P(x) be a real polynomial of degree 3 which vanishes at x = –3. Let P(x) have local minima at x = 1, local maxima at x = –1 and `int_-1^1 P(x)dx` = 18, then the sum of all the coefficients of the polynomial P(x) is equal to ______.


Find the area of the following region using integration ((x, y) : y2 ≤ 2x and y ≥ x – 4).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×