Advertisements
Advertisements
प्रश्न
The area between x-axis and curve y = cos x when 0 ≤ x ≤ 2 π is ___________ .
विकल्प
0
2
3
4
Advertisements
उत्तर
` 4`

Required shaded area,
\[A = \int_0^\frac{\pi}{2} \cos x dx + \int_\frac{\pi}{2}^\frac{3\pi}{2} \left( - \cos x \right)dx + \int_{3\frac{\pi}{2}}^{2\pi} \cos x dx\]
\[ = \int_0^\frac{\pi}{2} \cos x dx - \int_\frac{\pi}{2}^\frac{3\pi}{2} \cos x dx + \int_{3\frac{\pi}{2}}^{2\pi} \cos x dx\]
\[ = \left[ \sin x \right]_0^\frac{\pi}{2} - \left[ \sin x \right]_\frac{\pi}{2}^\frac{3\pi}{2} + \left[ \sin x \right]_{3\frac{\pi}{2}}^{2\pi} \]
\[ = \left[ \sin x \right]_0^\frac{\pi}{2} - \left[ \sin x \right]_\frac{\pi}{2}^\frac{3\pi}{2} + \left[ \sin x \right]_{3\frac{\pi}{2}}^{2\pi} \]
\[ = \left( 1 - 0 \right) - \left( - 1 - 1 \right) + \left[ 0 - \left( - 1 \right) \right]\]
\[ = 1 + 2 + 1\]
\[ = 4\text{ sq units }\]
APPEARS IN
संबंधित प्रश्न
Using integration, find the area of the region bounded by the triangle whose vertices are (−1, 2), (1, 5) and (3, 4).
Find the area of the region lying between the parabolas y2 = 4ax and x2 = 4ay.
Find the area of the circle 4x2 + 4y2 = 9 which is interior to the parabola x2 = 4y
Find the area of the region bounded by the curves y = x2 + 2, y = x, x = 0 and x = 3
Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is
A. 2 (π – 2)
B. π – 2
C. 2π – 1
D. 2 (π + 2)
Using the method of integration find the area bounded by the curve |x| + |y| = 1 .
[Hint: The required region is bounded by lines x + y = 1, x– y = 1, – x + y = 1 and
– x – y = 1].
Choose the correct answer The area of the circle x2 + y2 = 16 exterior to the parabola y2 = 6x is
A. `4/3 (4pi - sqrt3)`
B. `4/3 (4pi + sqrt3)`
C. `4/3 (8pi - sqrt3)`
D.`4/3 (4pi + sqrt3)`
The area bounded by the y-axis, y = cos x and y = sin x when 0 <= x <= `pi/2`
(A) 2 ( 2 −1)
(B) `sqrt2 -1`
(C) `sqrt2 + 1`
D. `sqrt2`
Using integration, find the area of region bounded by the triangle whose vertices are (–2, 1), (0, 4) and (2, 3).
The area enclosed between the curves y = loge (x + e), x = loge \[\left( \frac{1}{y} \right)\] and the x-axis is _______ .
Area lying between the curves y2 = 4x and y = 2x is
Solve the following :
Find the area of the region lying between the parabolas y2 = 4x and x2 = 4y.
The area of the region included between the parabolas y2 = 16x and x2 = 16y, is given by ______ sq.units
The area of triangle ΔABC whose vertices are A(1, 1), B(2, 1) and C(3, 3) is ______ sq.units
Find the area enclosed between y = cos x and X-axis between the lines x = `pi/2` and x ≤ `(3pi)/2`
Find the area of sector bounded by the circle x2 + y2 = 25, in the first quadrant−
Find the area enclosed between the circle x2 + y2 = 9, along X-axis and the line x = y, lying in the first quadrant
Find the area enclosed by the curve x = 3 cost, y = 2 sint.
Find the area of the region included between the parabola y = `(3x^2)/4` and the line 3x – 2y + 12 = 0.
Find the area of the region bounded by the curves x = at2 and y = 2at between the ordinate corresponding to t = 1 and t = 2.
Find the area of a minor segment of the circle x2 + y2 = a2 cut off by the line x = `"a"/2`
Calcualte the area under the curve y = `2sqrt(x)` included between the lines x = 0 and x = 1
Determine the area under the curve y = `sqrt("a"^2 - x^2)` included between the lines x = 0 and x = a.
Area lying between the curves `y^2 = 4x` and `y = 2x`
Let the area enclosed by the x-axis, and the tangent and normal drawn to the curve 4x3 – 3xy2 + 6x2 – 5xy – 8y2 + 9x + 14 = 0 at the point (–2, 3) be A. Then 8A is equal to ______.
Using Integration, find the area of triangle whose vertices are (– 1, 1), (0, 5) and (3, 2).
Find the area enclosed between 3y = x2, X-axis and x = 2 to x = 3.
