Question

The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are 60° and 30° respectively. Find the height of the tower.

Answer 1

Let the height of the tower be h m.

 In ∆ABP,

`tan60^@ = h/4`

`=>sqrt3=h/4`

⇒h=1.73×4=6.92 cm

In ∆ABQ

`tan30^@=h/9`

`=>1/sqrt3=h/9`

`=>h=9/sqrt3cm= 5.20 cm`

Using the given data, we are getting two different values of h, which is not possible.