Question

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.

Answer 1

Let AB be the tower and the angle of elevation from point C (on ground) is 30°.

In ΔABC,

`("AB")/("BC") = tan 30°`

`("AB")/(30) = 1/sqrt3`

AB = `(30)/sqrt3`

AB = `(30)/sqrt3 xxsqrt3/sqrt3`

AB = `10sqrt3` m

Therefore, the height of the tower is `10sqrt3` m.