Question

The age of a man is three times the age of his son. After 10 years, the age of the man will be double that of his son. Find their present ages.

Answer 1

Let the age of the son be x years.
Then, the man's age = 3x years.
After 10 years, their ages becomes
(x + 10) and (3x + 10) respectively.
As per given conditions,

`((x + 10))/((3x + 10)) = (1)/(2)`
⇒ 2x + 20 = 3x + 10
⇒  x = 10 years
Thus, the present age of the son is 10 years.
Then, the main's age = 30years.