Question

`sqrt7x^2-6x-13sqrt7=0` 

 

Answer 1

We write, 

`-66x=7x-13x `  as  `sqrt7x^2xx(-13sqrt7)=91x^2=7x xx(-13x)` 

∴`sqrt7x^2-6x-13sqrt7=0` 

⇒`sqrt7x^2+7x-13x-13sqrt7=0` 

⇒`sqrt7x(x+sqrt7)-13(x+sqrt7)=0` 

⇒`(x+sqrt7)(sqrt7x-13)=0` 

⇒`x+sqrt7=0`  or `sqrt 7x-13=0` 

⇒`x=-sqrt7 or x=13/sqrt7=(13sqrt7)/7` 

Hence, the roots of the given equation are`-sqrt7` and `13/sqrt7/7`