Question

Spin only magnetic moment of [MnBr₆]^4- is ______ B.M. (Round off to the closest integer)

विकल्प

• 6 B.M.

• 3 B.M.

• 10 B.M.

• 8 B.M.

Answer 1

Spin only magnetic moment of [MnBr₆]^4- is 6 B.M.

Explanation:

[MnBr₆]^4- 

x - 6 = - 4

x = + 2

Mn = [Ar] 3d⁵ 4s²

Mn²⁺ = [Ar] 3d⁵ 4s⁰ 

Mn²⁺ = [Ar]

So, the number of unpaired electrons (n) = 5

`mu = sqrt("n" ("n + 2"))`

`mu = sqrt(5 (5 + 2))`

= `sqrt35`

= 5.91 B.M. ≈ 6 B.M.