Question

Some heat is given to 120 g of water and its temp. rises by 10 K. When the same amount of heat is given to 60 g of oil, its temp. rises by 40 K. The Sp. heat of water is 4200 J/kgK. Calculate:
(a) The amount of heat in joules given to water,
(b) The specific heat capacity of the oil.

Answer 1

For water

m = 120 g = 0.12 kg

ΔT = 10 K

C = 4200 J/ KgK

Q = m x c x ΔT

   = 0.12 x 4200 x 10

   = 5040 J

For oil:

Q = 5040 J 

m = 60 g = 0.06 kg

ΔT = 40 K

C = `"Q"/("m" xx Δ"T")`

   = `5040/(0.06 xx 40)` = 2100 J/kgK