Advertisements
Advertisements
प्रश्न
Solve x2/3 + x1/3 - 2 = 0.
Advertisements
उत्तर
Given equation is x2/3 + x1/3 - 2 = 0
Putting x1/3 = y, the given equation becomes
y2 + y - 2 = 0
⇒ y2 + 2y - y - 2 = 0
⇒ y(y + 2) - 1(y + 2) = 0
⇒ (y + 2) (y - 1) = 0
⇒ y + 2 = 0 or y - 1 = 0
⇒ y = -2 or y = 1
But x1/3 = y
∴ x1/3 = -2 or x1/3 = 1
⇒ x =(-2)3 or x = (1)3
⇒ x = -8 or x = 1
Hence, roots are -8, 1.
संबंधित प्रश्न
Find the values of k for which the roots are real and equal in each of the following equation:
9x2 - 24x + k = 0
Find the values of k for which the roots are real and equal in each of the following equation:
x2 - 2kx + 7k - 12 = 0
Solve the following quadratic equation using formula method only
x2 - 4x - 1 = 0
Solve for x: (x2 - 5x)2 - 7(x2 - 5x) + 6 = 0; x ∈ R.
Determine whether the given quadratic equations have equal roots and if so, find the roots:
x2 + 5x + 5 = 0
Determine whether the given quadratic equations have equal roots and if so, find the roots:
x2 + 2x + 4 = 0
Find the value of k so that sum of the roots of the quadratic equation is equal to the product of the roots:
(k + 1)x2 + (2k + 1)x - 9 = 0, k + 1 ≠ 0.
Discuss the nature of the roots of the following quadratic equations : `2sqrt(3)x^2 - 5x + sqrt(3)` = 0
If (1 – p) is a root of the equation x2 + px + 1 – p = 0, then roots are:
State whether the following quadratic equation have two distinct real roots. Justify your answer.
3x2 – 4x + 1 = 0
