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प्रश्न
Solve the following system of equations graphically:
x − 2y = 3, 3x − 8y = 7
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उत्तर
Equations are,
x − 2y = 3 ...(1)
3x − 8y = 7 ...(2)
For Equation (1)
x − 2y = 3
Putting y = 0
x − 2(0) = 3
x = 3
So, x = 3, y = 0 is a solution
i.e., (3, 0) is a solution
x − 2y = 3
Putting y = 1
x − 2(1) = 3
x − 2 = 3
x = 3 + 2
x = 5
So x = 5 and y = 1 is a solution.
i.e., (5, 1) is a solution
Putting y = −2
x − 2(−2) = 3
x + 4 = 3
x = 3 − 4
x = −1
So x = −1 and y = −2 is a solution.
i.e., (−1, −2) is a solution
| x | 3 | 5 | −1 |
| y | 0 | 1 | −2 |
For Equation (2)
3x − 8y = 7
Putting y = 1
3x − 8(1) = 7
3x − 8 = 7
3x = 7 + 8
3x = 15
x = 5
So, x = 5, y = 1 is a solution
i.e., (5, 1) is a solution
3x − 8y = 7
Putting y = −2
3x − 8(−2) = 7
3x + 16 = 7
3x = 7 − 16
3x = −9
x = −3
So, x = −3, y = −2 is a solution
i.e., (−3, −2) is a solution
Putting y = 0
3x − 8(0) = 7
3x + 0 = 7
3x = 7
x = `7/3`
x = 2.3
So, x = 2.3, y = 0 is a solution
i.e., (2.3, 0) is a solution
| x | 5 | −3 | 2.3 |
| y | 1 | −2 | 0 |
We will plot both equations on the graph,

Since lines intersect at (5, 1)
∴ x = 5, y = 1 is the solution of the pair of equations.
