Advertisements
Advertisements
प्रश्न
Solve the following simultaneous equations:
65x - 33y = 97
33x - 65y = 1
Advertisements
उत्तर
The given equations are
65x - 33y = 97 ....(i)
33x - 65y = 1 ....(ii)
Multiplying eqn. (i) by 33 and eqn. (ii) by 65, we get
2145x - 1089y = 3201 ....(iii)
2145x - 4225y = 65 ....(iv)
Subtracting eqn. (iv) from eq. (iii), we get
3136y = 3136
⇒ y = 1
Substituting the value of y in eqn. (ii), we get
33x - 65(1) = 1
⇒ 33x - 65 = 1
⇒ 33x = 1 + 65
⇒ 33x = 66
⇒ x = 2
Thus, the solution set is (2, 1).
APPEARS IN
संबंधित प्रश्न
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
13 + 2y = 9x
3y = 7x
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`[5y]/2 - x/3 = 8`
`y/2 + [5x]/3 = 12`
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`1/5( x - 2 ) = 1/4( 1 - y )`
26x + 3y + 4 = 0
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
2x − 3y − 3 = 0
`[2x]/3 + 4y + 1/2` = 0
The value of expression mx - ny is 3 when x = 5 and y = 6. And its value is 8 when x = 6 and y = 5. Find the values of m and n.
Solve :
`[ 7 + x ]/5 - [ 2x - y ]/4 = 3y - 5`
`[5y - 7]/2 + [ 4x - 3 ]/6 = 18 - 5x`
Solve the following pairs of equations:
`(x + y)/(xy)` = 2
`(x - y)/(xy)` = 6
If 10y = 7x - 4 and 12x + 18y = 1 ; find the value of 4x + 6y and 8y - x.
`4x + 6/y = 15 and 6x - 8/y = 14.` Hence, find a if y = ax - 2.
The sum of the numerator and denominator of a fraction is 12. If the denominator is increased by 3, the fraction becomes `(1)/(2)`. Find the fraction.
