हिंदी

Solve the following pair of linear equation by the elimination method and the substitution method: x + y = 5 and 2x – 3y = 4 - Mathematics

Advertisements
Advertisements

प्रश्न

Solve the following pair of linear equation by the elimination method and the substitution method:

x + y = 5 and 2x – 3y = 4

योग
Advertisements

उत्तर

x + y = 5 and 2x – 3y = 4

By elimination method

x + y = 5       ...(i)

2x – 3y = 4    ...(ii)

Multiplying equation (i) by (ii), we get

2x + 2y = 10        ...(iii)

2x – 3y = 4        ...(ii)

Subtracting equation (ii) from equation (iii), we get

5y = 6

y = `6/5`

Putting the value in equation (i), we get

`x = 5 - (6/5) = 19/5`

Hence, `x = 19/5 and y = 6/5`

By substitution method

x + y = 5        ...(i)

Subtracting y both side, we get

x = 5 - y        ...(iv)

Putting the value of x in equation (ii) we get

2(5 – y) – 3y = 4

-5y = -6

`y = (-6)/-5`

`y = 6/5`

Putting the value of y in equation (iv) we get

`x = 5  –  6/5`

`x = 19/5`

Hence, `x = 19/5` and `y = 6/5`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Pair of Linear Equations in Two Variables - Exercise 3.4 [पृष्ठ ५६]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 3 Pair of Linear Equations in Two Variables
Exercise 3.4 | Q 1.1 | पृष्ठ ५६

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Solve the following system of equations by using the method of elimination by equating the co-efficients.

`\frac { x }{ y } + \frac { 2y }{ 5 } + 2 = 10; \frac { 2x }{ 7 } – \frac { 5 }{ 2 } + 1 = 9`


Solve for x and y : `\frac { ax }{ b } – \frac { by }{ a } = a + b ; ax – by = 2ab`


Solve (a – b) x + (a + b) y = `a^2 – 2ab – b^2 (a + b) (x + y) = a^2 + b^2`


Solve the following pair of linear equation by the elimination method and the substitution method.

`x/2 + (2y)/3 = -1 and x - y /3 = 3`


Form the pair of linear equation in the following problem, and find its solution (if they exist) by the elimination method:

Meena went to a bank to withdraw ₹ 2000. She asked the cashier to give her ₹ 50 and ₹ 100 notes only. Meena got 25 notes in all. Find how many notes of ₹ 50 and ₹ 100 she received.


Out of 1900 km, Vishal travelled some distance by bus and some by aeroplane. The bus travels with an average speed of 60 km/hr and the average speed of the aeroplane is 700 km/hr. It takes 5 hours to complete the journey. Find the distance, Vishal travelled by bus.


In an envelope there are some 5 rupee notes and some 10 rupee notes. Total amount of these notes together is 350 rupees. Number of 5 rupee notes are less by 10 than twice number of 10 rupee notes. Then find the number of 5 rupee and 10 rupee notes.


The sum of the digits in a two-digits number is 9. The number obtained by interchanging the digits exceeds the original number by 27. Find the two-digit number.


A fraction becomes `1/3` when 2 is subtracted from the numerator and it becomes `1/2` when 1 is subtracted from the denominator. Find the fraction.


A fraction becomes `(1)/(3)` when 2 is subtracted from the numerator and it becomes `(1)/(2)` when 1 is subtracted from the denominator. Find the fraction.


Complete the activity.


The sum of the two-digit number and the number obtained by interchanging the digits is 132. The digit in the ten’s place is 2 more than the digit in the unit’s place. Complete the activity to find the original number.

Activity: Let the digit in the unit’s place be y and the digit in the ten’s place be x.

∴ The number = 10x + y

∴ The number obtained by interchanging the digits = `square`

∴ The sum of the number and the number obtained by interchanging the digits = 132

∴ 10x + y + 10y + x = `square`

∴ x + y = `square`      .....(i)

By second condition,

Digit in the ten’s place = digit in the unit’s place + 2

∴ x – y = 2     ......(ii)

Solving equations (i) and (ii)

∴ x = `square`, y = `square`

Ans: The original number = `square`


The length of the rectangle is 5 more than twice its breadth. The perimeter of a rectangle is 52 cm, then find the length of the rectangle


The semi perimeter of a rectangular shape garden is 36 m. The length of the garden is 4 m more than its breadth. Find the length and the breadth of the garden


The angles of a triangle are x, y and 40°. The difference between the two angles x and y is 30°. Find x and y.


The age of the father is twice the sum of the ages of his two children. After 20 years, his age will be equal to the sum of the ages of his children. Find the age of the father.


The angles of a cyclic quadrilateral ABCD are ∠A = (6x + 10)°, ∠B = (5x)°, ∠C = (x + y)°, ∠D = (3y – 10)°. Find x and y, and hence the values of the four angles. 


Evaluate: (1004)3


The ratio of two numbers is 2:3. If 5 is added in each numbers, then the ratio becomes 5:7 find the numbers.

The ratio of two numbers is 2:3.

So, let the first number be 2x and the second number be `square`.

From the given condition,

`((2x) + square)/(square + square) = square/square`

`square (2x + square) = square (square + square)`

`square + square = square + square`

`square - square = square - square`

`- square = - square`

x = `square`

So, The first number = `2 xx square = square`

and, Second number =  `3 xx square = square`

Hence, the two numbers are `square` and `square`


A 2-digit number is such that the product of its digits is 24. If 18 is subtracted from the number, the digits interchange their places. Find the number.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×