हिंदी

Solve: sin^–1 (x) + sin^–1 (1 – x) = cos^–1 x - Mathematics

Advertisements
Advertisements

प्रश्न

Solve:

sin–1 (x) + sin–1 (1 – x) = cos–1 x

योग
Advertisements

उत्तर

sin–1 (x) + sin–1 (1 – x) = cos–1 x

⇒ `sin^-1(x) + sin^-1(1 - x) = π/2 - sin^-1x`

⇒ `sin^-1(1 - x) = π/2 - 2sin^-1x`

⇒ `(1 - x) = sin(π/2 - 2sin^-1x)`

⇒ (1 – x) = cos (2 sin–1 x)

⇒ (1 – x) = cos (cos–1 (1 – 2x2))

⇒ (1 – x) = 1 – 2x2

⇒ 2x2 – x = 0

∴ x = `0, 1/2`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2024-2025 (March) Specimen Paper

वीडियो ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्न

Prove the following:

3 sin−1 x = sin−1 (3x − 4x3), `x ∈ [-1/2, 1/2]`


Prove `tan^(-1)  2/11 + tan^(-1)  7/24 = tan^(-1)  1/2`


Write the function in the simplest form: `tan^(-1)  1/(sqrt(x^2 - 1)), |x| > 1`


Find the value of the following:

`tan  1/2 [sin^(-1)  (2x)/(1+ x^2) + cos^(-1)  (1-y^2)/(1+y^2)]`, |x| < 1, y > 0 and xy < 1


Prove that:

`cos^(-1)  12/13 + sin^(-1)  3/5 = sin^(-1)  56/65`


Prove that:

`tan^(-1)  63/16 = sin^(-1)  5/13 + cos^(-1)  3/5`


Prove that `3sin^(-1)x = sin^(-1) (3x - 4x^3)`, `x in [-1/2, 1/2]`


Prove that

\[2 \tan^{- 1} \left( \frac{1}{5} \right) + \sec^{- 1} \left( \frac{5\sqrt{2}}{7} \right) + 2 \tan^{- 1} \left( \frac{1}{8} \right) = \frac{\pi}{4}\] .

 

If cos-1 x + cos -1 y + cos -1 z = π , prove that x2 + y2 + z2 + 2xyz = 1.


If y = `(x sin^-1 x)/sqrt(1 -x^2)`, prove that: `(1 - x^2)dy/dx = x + y/x`


Find the value of the expression in terms of x, with the help of a reference triangle

sin (cos–1(1 – x))


Choose the correct alternative:

sin–1(2 cos2x – 1) + cos1(1 – 2 sin2x) =


Evaluate `tan^-1(sin((-pi)/2))`.


Evaluate: `sin^-1 [cos(sin^-1 sqrt(3)/2)]`


Evaluate `cos[sin^-1  1/4 + sec^-1  4/3]`


Show that `tan(1/2 sin^-1  3/4) = (4 - sqrt(7))/3` and justify why the other value `(4 + sqrt(7))/3` is ignored?


If cos–1α + cos–1β + cos–1γ = 3π, then α(β + γ) + β(γ + α) + γ(α + β) equals ______.


If `"tan"^-1 ("cot"  theta) = 2theta, "then"  theta` is equal to ____________.


If `"cot"^-1 (sqrt"cos" alpha) - "tan"^-1 (sqrt"cos" alpha) = "x",` the sinx is equal to ____________.


The value of `"tan"^-1 (3/4) + "tan"^-1 (1/7)` is ____________.


If `"tan"^-1 2  "x + tan"^-1 3  "x" = pi/4`, then x is ____________.


The value of `"cos"^-1 ("cos" ((33pi)/5))` is ____________.


`"cos"^-1 1/2 + 2  "sin"^-1 1/2` is equal to ____________.


The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

Measure of ∠DAB = ________.


The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

𝐴' Is another viewer standing on the same line of observation across the road. If the width of the road is 5 meters, then the difference between ∠CAB and ∠CA'B is ______.


`tan^-1  1/2 + tan^-1  2/11` is equal to


Find the value of `cos^-1 (1/2) + 2sin^-1 (1/2) ->`:-


`50tan(3tan^-1(1/2) + 2cos^-1(1/sqrt(5))) + 4sqrt(2) tan(1/2tan^-1(2sqrt(2)))` is equal to ______.


Find the value of `tan^-1 [2 cos (2 sin^-1  1/2)] + tan^-1 1`.


If `tan^-1 ((x - 1)/(x + 1)) + tan^-1 ((2x - 1)/(2x + 1)) = tan^-1 (23/36)` = then prove that 24x2 – 23x – 12 = 0


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×