Advertisements
Advertisements
प्रश्न
Solve the quadratic equation 2x2 + ax − a2 = 0 for x.
Advertisements
उत्तर
We have:
2x2 + ax − a2 = 0
Comparing the given equation with the standard quadratic equation (ax2 + bx + c = 0), we get:
a=2,b=a and c=-a2
Using the quadratic formula ,`x=(-b+-sqrt(b^2-4ac)/(2a))` , We get:
`x=-a+-sqrt(a^2-4xx2xx(-a^2))/(2xx2)`
`=(-a+sqrt(9a^2))4=(-a+3a)/4`
`=>x=(-a+3a)/4=a/2 or x=(-a-3a)/4=-a`
So, the solutions of the given quadratic equation are x=a/2 or x=-a
APPEARS IN
संबंधित प्रश्न
If -5 is a root of the quadratic equation 2x2 + px – 15 = 0 and the quadratic equation p(x2 + x)k = 0 has equal roots, find the value of k.
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx - 4 = 0
Find the value(s) of k so that the quadratic equation 3x2 − 2kx + 12 = 0 has equal roots ?
Solve the following quadratic equation using formula method only
3x2 + 12 = 32 x
`10x -(1)/x` = 3
Form the quadratic equation whose roots are:
`sqrt(3) and 3sqrt(3)`
Find the discriminant of the following equations and hence find the nature of roots: 2x2– 3x + 5 = 0
If roots of a quadratic equation 3y2 + ky + 12 = 0 are real and equal, then find the value of ‘k’.
Every quadratic equation has at least one real root.
If 3 is a root of the quadratic equation x2 – px + 3 = 0, then p is equal to ______.
