Advertisements
Advertisements
प्रश्न
Solve for x and y :
`[ y + 7 ]/5 = [ 2y - x ]/4 + 3x - 5`
`[ 7 - 5x ]/2 + [ 3 - 4y ]/6 = 5y - 18`
Advertisements
उत्तर
The given pair of linear equation are
`[ y + 7 ]/5 = [ 2y - x ]/4 + 3x - 5`
⇒ 55x + 6y = 128 ....(1)[ On simplifying ]
`[ 7 - 5x ]/2 + [ 3 - 4y ]/6 = 5y - 18`
⇒ 15x + 34y = 132 ....(2)[ On simplifying ]
Multiply equation (1) by 3 and equation (2) by 11, we get :
165x + 18y = 384 ....(3)
165x + 374y = 1452 .....(4)
Subtracting (4) from (3)
165x + 18y = 384
- 165x + 374y = 1452
- - -
- 356y = - 1068
y = 3
Substituting y = 3 in equation (1), we get
55x + 6(3) = 128
⇒ 55x = 110
⇒ x = 2
∴ Solution is x = 2 and y = 3.
APPEARS IN
संबंधित प्रश्न
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
3x - y = 23
`x/3 + y/4 = 4`
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
13x+ 11y = 70
11x + 13y = 74
Find the value of m, if x = 2, y = 1 is a solution of the equation 2x + 3y = m.
10% of x + 20% of y = 24
3x - y = 20
Solve :
`[ 7 + x ]/5 - [ 2x - y ]/4 = 3y - 5`
`[5y - 7]/2 + [ 4x - 3 ]/6 = 18 - 5x`
Solve the following simultaneous equation :
8v - 3u = 5uv
6v - 5u = -2uv
Solve the following pairs of equations:
`(3)/(5) x - (2)/(3) y + 1` = 0
`(1)/(3) y + (2)/(5) x ` = 4
Solve the following pairs of equations:
y - x = 0.8
`(13)/(2(x + y)) = 1`
If 2 is added to the numerator and denominator it becomes `(9)/(10)` and if 3 is subtracted from the numerator and denominator it becomes `(4)/(5) `Find the fraction.
Two mobiles S1 and S2 are sold for Rs. 10,490 making 4% profit on S1 and 6% on S2. If the two mobiles are sold for Rs.10,510, a profit of 6% is made on S1 and 4% on S2. Find the cost price of both the mobiles.
