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प्रश्न
Solve for x and give your answer correct to 2 decimal places:
3x2 – 32x + 12 = 0
योग
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उत्तर
Given: 3x2 – 32x + 12 = 0
Step-wise calculation:
1. Identify coefficients: a = 3, b = –32, c = 12.
2. Use the quadratic formula `x = (-b ± sqrt((b^2 - 4ac)))/(2a)`.
3. Compute the discriminant:
D = (–32)2 – 4 × 3 × 12
= 1024 – 144
= 880
Since D > 0, the equation has two distinct real roots.
4. `sqrt(D) = sqrt(880)`
= `4sqrt(55)`
= 29.66479395
5. `x = (32 ± 29.66479395)/6`
`x_1 = (32 + 29.66479395)/6`
= `61.66479395/6`
= 10.27746566
= 10.28 ...(To 2 d.p.)
`x_2 = (32 - 29.66479395)/6`
= `2.33520605/6`
= 0.38920101
= 0.39 ...(To 2 d.p.)
x = 10.28 or x = 0.39.
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