Question

Solve the following equation and verify your answer:

\[\frac{2x}{3x + 1} = - 3\]

Answer 1

\[\frac{2x}{3x + 1} = - 3\]

\[\text{ or }2x = - 9x - 3 [\text{ After cross multiplication }]\]

\[\text{ or }2x + 9x = - 3\]

\[\text{ or }11x = - 3\]

\[\text{ or }x = \frac{- 3}{11}\]

\[\text{ Thus, }x = \frac{- 3}{11}\text{ is the solution of the given equation .} \]

\[\text{ Check: }\]

\[\text{ Substituting }x = \frac{- 3}{11}\text{ in the given equation, we get: }\]

\[\text{ L . H . S . }= \frac{2(\frac{- 3}{11})}{3(\frac{- 3}{11}) + 1} = \frac{- 6}{- 9 + 11} = \frac{- 6}{2} = - 3\]

\[\text{ R . H . S . }= - 3\]

\[ \therefore\text{ L . H . S . = R . H . S . for }x = \frac{- 3}{11}\]