Advertisements
Advertisements
प्रश्न
Solve the following equation: `(2"x")/("x" - 4) + (2"x" - 5)/("x" - 3) = 25/3`
Advertisements
उत्तर
`(2"x")/("x" - 4) + (2"x" - 5)/("x" - 3) = 25/3`
`(6 "x")/("x" - 4) + (6"x" - 15)/("x" - 3) = 25`
6x (x- 3)+ (6x- 15) (x- 4) = 25 (x- 4) (x-3)
6x2 -18x + 6x2 - 15x - 24x + 60 = 25 (x2 - 4x - 3x + 12)
12x2 - 57x + 60 = 25x2 - 175 x + 300
13x2 - 118 x + 240 = 0
`"x"^2 - 118/13 "x" + 240/13 = 0`
`"x"^2 - 6"x" - 40/13 "x" + 240/13 = 0`
`"x" ("x" - 6) - 40/13 ("x" - 6) = 0`
`("x" + 6)("x" - 40/13) = 0`
x = 6 , x = `40/13`
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`1/(x - 1) - 1/(x + 5) = 6/7, x ≠ 1, -5`
Find the whole numbers which when decreased by 20 is equal to 69 times the reciprocal of the members.
The sum of a numbers and its positive square root is `6/25`. Find the numbers.
In a class test, the sum of the marks obtained by P in Mathematics and science is 28. Had he got 3 marks more in mathematics and 4 marks less in Science. The product of his marks would have been 180. Find his marks in two subjects.
Solve the following quadratic equations by factorization: \[\frac{5 + x}{5 - x} - \frac{5 - x}{5 + x} = 3\frac{3}{4}; x \neq 5, - 5\]
If the sum of the roots of the equation \[x^2 - \left( k + 6 \right)x + 2\left( 2k - 1 \right) = 0\] is equal to half of their product, then k =
Three years ago, a man was 5 times the age of his son. Four years hence, he will be thrice his son's age. Find the present ages of the man and his son.
Solve equation using factorisation method:
x(x – 5) = 24
Solve the following equation by factorization
x(2x + 5) = 3
Solve the following equation by factorization
`x + (1)/x = 2(1)/(20)`
