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`Sin^-1{Cos(Sin^-1 Sqrt3/2)}` - Mathematics

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प्रश्न

`sin^-1{cos(sin^-1  sqrt3/2)}`

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उत्तर

`sin^-1{cos(sin^-1  sqrt3/2)}=sin^-1{cos(sin^-1  sin    pi/3)}`

`=sin^-1{cos(pi/3)}`

`=sin^-1{1/2}`

`=sin^-1{sin  pi/6}`

`=pi/6`

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.01 [पृष्ठ ७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.01 | Q 2.2 | पृष्ठ ७

वीडियो ट्यूटोरियलVIEW ALL [3]

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