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प्रश्न
Simplify the following and express with positive index:
`[ 1 - { 1 - ( 1 - n )^-1}^-1]^-1`
योग
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उत्तर
`[ 1 - { 1 - ( 1 - n )^-1}^-1]^-1`
= `[1 - { 1 - 1/( 1 - n ) }^-1]^-1`
= `[1 - { (1-n-1)/( 1 - n ) }^-1]^-1`
= `[1 - { (-n)/( 1 - n ) }^-1]^-1`
= `[1 - { (1-n)/(- n ) }]^-1`
= `[ (-n- 1 + n )/-n ]^-1`
= `[(-1)/-n]^-1`
= n
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