Advertisements
Advertisements
प्रश्न
Simplify
sin A `[[sinA -cosA],["cos A" " sinA"]] + cos A[[ cos A" sin A " ],[-sin A" cos A"]]`
Advertisements
उत्तर
sin A `[[sinA -cosA],["cos A" " sinA"]] + cos A [[ cos A" sin A " ],[-sin A" cos A"]]`
= ` [[sin^2A " - sin A cos A"],[sinA .cos A - sin^2 A ]]+ [[cos^2 A " cos A . sin A"],[ -sinA cos A cos^2 A]]`
` =[[sin^2 A + cos^2 A " - sin A. cos A + cos A . sin A "],[sin A . cos A - sin A . cos A " sin^2 A + cos^2 A]] = [[ 1 0 ] , [ 0 1]]`
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities
`(1 + tan^2 theta)/(1 + cot^2 theta) = ((1 - tan theta)/(1 - cot theta))^2 = tan^2 theta`
Prove the following trigonometric identities.
`(cot A - cos A)/(cot A + cos A) = (cosec A - 1)/(cosec A + 1)`
Prove the following trigonometric identities.
`(tan^2 A)/(1 + tan^2 A) + (cot^2 A)/(1 + cot^2 A) = 1`
` (sin theta - cos theta) / ( sin theta + cos theta ) + ( sin theta + cos theta ) / ( sin theta - cos theta ) = 2/ ((2 sin^2 theta -1))`
If a cos θ + b sin θ = 4 and a sin θ − b sin θ = 3, then a2 + b2 =
Without using trigonometric identity , show that :
`sec70^circ sin20^circ - cos20^circ cosec70^circ = 0`
Prove that `tan A/(1 + tan^2 A)^2 + cot A/(1 + cot^2 A)^2 = sin A.cos A`
Prove the following identities.
`sqrt((1 + sin theta)/(1 - sin theta)) + sqrt((1 - sin theta)/(1 + sin theta))` = 2 sec θ
Prove the following identities.
`(sin "A" - sin "B")/(cos "A" + cos "B") + (cos "A" - cos "B")/(sin "A" + sin "B")`
Given that sinθ + 2cosθ = 1, then prove that 2sinθ – cosθ = 2.
