Advertisements
Advertisements
प्रश्न
Simplify
sin A `[[sinA -cosA],["cos A" " sinA"]] + cos A[[ cos A" sin A " ],[-sin A" cos A"]]`
Advertisements
उत्तर
sin A `[[sinA -cosA],["cos A" " sinA"]] + cos A [[ cos A" sin A " ],[-sin A" cos A"]]`
= ` [[sin^2A " - sin A cos A"],[sinA .cos A - sin^2 A ]]+ [[cos^2 A " cos A . sin A"],[ -sinA cos A cos^2 A]]`
` =[[sin^2 A + cos^2 A " - sin A. cos A + cos A . sin A "],[sin A . cos A - sin A . cos A " sin^2 A + cos^2 A]] = [[ 1 0 ] , [ 0 1]]`
APPEARS IN
संबंधित प्रश्न
Prove that:
`tanA/(1 - cotA) + cotA/(1 - tanA) = secA "cosec" A + 1`
Show that : `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec A cosec A`
What is the value of (1 + cot2 θ) sin2 θ?
What is the value of \[\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}\]
Write True' or False' and justify your answer the following:
\[ \cos \theta = \frac{a^2 + b^2}{2ab}\]where a and b are two distinct numbers such that ab > 0.
If x = r sin θ cos ϕ, y = r sin θ sin ϕ and z = r cos θ, then
Prove the following identity :
secA(1 + sinA)(secA - tanA) = 1
Prove the following identities:
`(1 - tan^2 θ)/(cot^2 θ - 1) = tan^2 θ`.
Prove that `(cos^2θ)/(sinθ) + sin θ = "cosec" θ`.
If tan θ = 3, then `(4 sin theta - cos theta)/(4 sin theta + cos theta)` is equal to ______.
