Advertisements
Advertisements
प्रश्न
Show that the value of x3 – 8x2 + 12x – 5 is zero, when x = 1.
योग
Advertisements
उत्तर
x3 – 8x2 + 12x – 5
= (1)3 − 8(1)2 + 12(1) − 5
= 1 − 8 + 12 − 5
= 13 − 13
= 0
Hence proved.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the value of `"yx"/"z"`, when x = 8, y = 4 and z = 16
If x = 2, y = 5 and z = 4, find the value of the following:
yx
Evaluate:
35b – (16b + 9b)
Simplify:
12x − (5x + 2x)
Simplify:
`3"x"+(2"x"-overline("x"+2))`
Simplify:
p + 2 (q − r − p)
Simplify:
`"a"−[−{−(a−overline("b"-"c"))}]`
If x = 3, y = 2 and z = 1; find the value of xy + y2z – 4zx
Simplify:
3x – 8 (5x – 10)
Simplify:
`8"x"−(3"x"−overline(2"x"-3))`
