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प्रश्न
Show that the value of x3 – 8x2 + 12x – 5 is zero, when x = 1.
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उत्तर
x3 – 8x2 + 12x – 5
= (1)3 − 8(1)2 + 12(1) − 5
= 1 − 8 + 12 − 5
= 13 − 13
= 0
Hence proved.
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
y × d = .............
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
a − b + y = ................
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
xy − bd = ..............
Find the value of 5x + 3y − 6z, when x = 3, y = 5 and z = 4
Find the value of 4pq × 2r, when p = 5, q = 3 and r = 1/2
If a = 3, b = 0, c = 2 and d = 1, find the value of abc − bcd + cda
Simplify:
3x + (8x − 5x) − (7x − x)
Simplify:
x − [y + {x − (y + x)}]
Simplify:
4x + 3 (2x − 5y)
Substitute m = 3 into 5 + \[\frac{m}{2}\]:
