हिंदी

Show Hat A(1,2), B(4,3),C(6,6) and D(3,5) Are the Vertices of a Parallelogram. Show that Abcd is Not Rectangle.

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प्रश्न

Show hat A(1,2), B(4,3),C(6,6) and D(3,5) are the vertices of a parallelogram. Show that ABCD is not rectangle.

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उत्तर

The given vertices are  A(1,2), B(4,3),C(6,6) and D(3,5) .

`AB = sqrt((1-4)^2+(2-3)^2) = sqrt((-3)^2 +(-1)^2) `

`= sqrt(9+1) = sqrt(10) `

`BC = sqrt((4-6)^2 +(3-6)^2) = sqrt((-2)^2 +(-3)^2)`

`= sqrt(4+9) = sqrt(13)`

`CD = sqrt((6-3) ^2 +(6-5)^2) = sqrt((3)^2 +(1)^2) `

`= sqrt(9+1) = sqrt(10)`

`AD = sqrt((1-3)^2 +(2-5)^2 ) = sqrt((-2)^2 +(-3)^2)`

`= sqrt(4+9) = sqrt(13) `

`∵ AB =  CD = sqrt(10) " units and"  BC= AD = sqrt(13)   units `

Therefore, ABCD is a parallelogram

`AC = sqrt((1-6)^2 +(2-6)^2 )= sqrt((-5)^2 +(-4)^2)`

`= sqrt(25+16) = sqrt(41) `

`BD = sqrt((4-3)^2 +(3-5)^2 ) = sqrt((1)^2 +(-2)^2) `

`= sqrt(1+4) = sqrt(5) `

Thus, the diagonal AC and BD are not equal and hence ABCD is not a rectangle

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अध्याय 6: Coordinate Geometry - Exercises 1

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 6 Coordinate Geometry
Exercises 1 | Q 31

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