Advertisements
Advertisements
प्रश्न
Rohit borrowed Rs. 24,000 at 7.5 percent per year. How much money will he pay at the end of the 4th years to clear his debt?
Advertisements
उत्तर
Principal (P) = Rs.24,000
Rate (R) = 7.5% P.A.
Time (T) = 4 years
S.I. =`("P"xx"T"xx"R")/100`
= Rs.`(24,000xx4xx7.5)/100`
= Rs. 240 × 4 × 7.5
= 240 × 30
= Rs. 7200
A = P + S.I
A = 24000 + 7200
A = 31200
A = Rs. 31,200
Amount needed to clear the debt at the end of 4th year
= Rs. 24000 + Rs. 7200 = Rs. 31,200
APPEARS IN
संबंधित प्रश्न
Find the amount to be paid at the end of 3 years in given case:
Principal = ₹ 1,200 at 12% p.a.
Find the interest and the amount on:
₹ 750 in 3 years 4 months at 10% per annum.
Find the principal which will amount to Rs. 4,000 in 4 years at 6.25% Per annum.
Anita takes a loan of Rs. 5,000 at 15% per year as the rate of interest. Find the interest she has to pay at the end of one year.
The time period after which the interest is added each time to form a new principal is called the ______.
The simple interest on a sum of ₹ P for T years at R% per annum is given by the formula: Simple Interest = `(T xx P xx R)/100`.
Chalk contains 10% calcium, 3% carbon and 12% oxygen. Find the amount of carbon and calcium (in grams) in `2 1/2` kg of chalk.
₹ 9000 becomes ₹ 18000 at simple interest in 8 years. Find the rate per cent per annum.
In how many years will the simple interest on a certain sum be 4.05 times the principal at 13.5 per cent per annum?
