Advertisements
Advertisements
प्रश्न
Rohit borrowed Rs. 24,000 at 7.5 percent per year. How much money will he pay at the end of the 4th years to clear his debt?
Advertisements
उत्तर
Principal (P) = Rs.24,000
Rate (R) = 7.5% P.A.
Time (T) = 4 years
S.I. =`("P"xx"T"xx"R")/100`
= Rs.`(24,000xx4xx7.5)/100`
= Rs. 240 × 4 × 7.5
= 240 × 30
= Rs. 7200
A = P + S.I
A = 24000 + 7200
A = 31200
A = Rs. 31,200
Amount needed to clear the debt at the end of 4th year
= Rs. 24000 + Rs. 7200 = Rs. 31,200
APPEARS IN
संबंधित प्रश्न
If Meena gives an interest of ₹ 45 for one year at 9% rate p.a.. What is the sum she has borrowed?
On what principal will the simple interest be Rs. 7,008 in 6 years 3 months at 5% per year?
The interest on a certain sum of money is 0.24 times itself in 3 years. Find the rate of interest.
Vilasrao borrowed Rs. 20000 from a bank at a rate of 8 p.c.p.a. What is the amount he will return to the bank at the end of the year?
Aravind borrowed a sum of ₹ 8,000 from Akash at 7% per annum. Find the interest and amount to be paid at the end of two years
In what time will ₹ 17800 amount to ₹ 19936 at 6% per annum?
Interest on ₹ 12000 for 1 month at the rate of 10% per annum is ______.
The simple interest on a sum of ₹ P for T years at R% per annum is given by the formula: Simple Interest = `(T xx P xx R)/100`.
Chalk contains 10% calcium, 3% carbon and 12% oxygen. Find the amount of carbon and calcium (in grams) in `2 1/2` kg of chalk.
Bhavya earns ₹ 50,000 per month and spends 80% of it. Due to pay revision, her monthly income increases by 20% but due to price rise, she has to spend 20% more. Find her new savings.
