Advertisements
Advertisements
प्रश्न
Rohit borrowed ₹ 40,000 for 2 years at 10% per annum C.I. and Manish borrowed the same sum for the same time at 10.5% per annum simple interest. Which of these two gets less interest and by how much?
Advertisements
उत्तर
Sum borrowed (P) = ₹40000
Rate (R) = 10% p.a. compounded annually
Time (T) = 2 years
∴ Interest for the first year =`"PRT"/100`
`=₹(40000xx10xx1)/100`
= ₹4000
Amount after one year = ₹40000 + 4000
= ₹44000
Principal for the second year = ₹44000
∴ Interest for the second year
`=(44000xx10xx1)/100`
= ₹4400
∴ Compound Interest for 2 years = ₹4000 + 4400
= ₹8400
In the second case,
Principal (P) = ₹40000
Rate (R) = 10.5% p.a.
Time (T) = 2 years
∴ Simple Interest = `"PRT"/100=(40000xx10.5xx2)/100`
`=₹(40000xx105xx2)/(100xx10)`
= ₹8400
In both the cases, interest is same.
APPEARS IN
संबंधित प्रश्न
What will Rs 125000 amount to at the rate of 6%, if the interest is calculated after every 3 months?
A certain sum amounts to Rs. 5,292 in two years and Rs. 5,556.60 in three years, interest being compounded annually. Find : the rate of interest.
A sum of Rs. 8,000 is invested for 2 years at 10% per annum compound interest. Calculate:
(i) interest for the first year.
(ii) principal for the second year.
(iii) interest for the second year.
(iv) the final amount at the end of the second year
(v) compound interest earned in 2 years.
Peter borrows ₹ 12,000 for 2 years at 10% p.a. compound interest. He repays ₹ 8,000 at the end of the first year. Find:
- the amount at the end of the first year, before making the repayment.
- the amount at the end of the first year, after making the repayment.
- the principal for the second year.
- the amount to be paid at the end of the second year, to clear the account.
The simple interest on a certain sum of money at 4% p.a. for 2 years is Rs1500. What will be the compound interest on the same sum for the same time?
The simple interest on a certain sum for 3 years at 4% is Rs 600. Find the compound interest for the same sum at the same percent and in the same time.
The compound interest on ₹ 5000 at 12% p.a for 2 years, compounded annually is ___________
The present value of a machine is ₹ 16800. It depreciates at 25% p.a. Its worth after 2 years is ₹ 9450
The time taken for ₹ 4400 to become ₹ 4851 at 10%, compounded half yearly is _______
Suppose for the principal P, rate R% and time T, the simple interest is S and compound interest is C. Consider the possibilities.
- C > S
- C = S
- C < S
Then
