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Represent the Following Families of Curves by Forming the Corresponding Differential Equations (A, B Being Parameters): X2 + (Y − B)2 = 1 - Mathematics

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प्रश्न

Represent the following families of curves by forming the corresponding differential equations (a, b being parameters):
x2 + (y − b)2 = 1

योग
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उत्तर

The equation of family of curves is \[x^2 + \left( y - b \right)^2 = 1.........(1)\]

where `b` is a parameter.

As this equation contains only one arbitrary constant, we shall get a differential equation of first order.

Differentiating (1) with respect to x, we get

\[2x + 2\left( y - b \right)\frac{dy}{dx} = 0\]

\[ \Rightarrow 2x + 2\sqrt{1 - x^2}\frac{dy}{dx} = 0 .......\left[ \text{Using }\left( 1 \right) \right]\]

\[ \Rightarrow x = - \sqrt{1 - x^2}\frac{dy}{dx}\]

\[ \Rightarrow x^2 = \left( 1 - x^2 \right) \left( \frac{dy}{dx} \right)^2 \]

\[ \Rightarrow x^2 = \left( \frac{dy}{dx} \right)^2 - x^2 \left( \frac{dy}{dx} \right)^2 \]

\[ \Rightarrow x^2 \left[ 1 + \left( \frac{dy}{dx} \right)^2 \right] = \left( \frac{dy}{dx} \right)^2 \]

It is the required differential equation.

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अध्याय 22: Differential Equations - Exercise 22.02 [पृष्ठ १७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 22 Differential Equations
Exercise 22.02 | Q 16.04 | पृष्ठ १७

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