Question

Ravish has three boxes whose total weight is \[60\frac{1}{2}\]  kg. Box B weighs \[3\frac{1}{2}\] kg more than box A and box C weighs \[5\frac{1}{3}\] kg more than box B. Find the weight of box A.

Answer 1

Let the weight of box A be x kg . 
Therefore, the weights of box B and box C will be\[ (x + 3\frac{1}{2}) kg\text{ and }(x + 3\frac{1}{2} + 5\frac{1}{3})\text{ kg, respectively .} \]
According to the question, 
\[x + (x + 3\frac{1}{2}) + (x + 3\frac{1}{2} + 5\frac{1}{3}) = 60\frac{1}{2}\]
or \[ 3x = \frac{121}{2} - \frac{7}{2} - \frac{7}{2} - \frac{16}{3}\]
or \[3x = \frac{363 - 21 - 21 - 32}{6}\]
or \[3x = \frac{289}{6}\]
or \[x = \frac{289}{18}\]
Thus, weight of box A = \[\frac{289}{18} kg\]