Advertisements
Advertisements
प्रश्न
Prove the following: sin230° + cos230° = `(1)/(2)sec60°`
Advertisements
उत्तर
L.H.S.
= sin230° + cos230°
= `(1/2)^2 + (sqrt(3)/2)^2`
= `(1)/(4) + (3)/(4)`
= `(4)/(4)`
= 1
= `(1)/(2) xx sec60°`
= R.H.S.
APPEARS IN
संबंधित प्रश्न
If 2 cos 2A = `sqrt3` and A is acute,
find:
(i) A
(ii) sin 3A
(iii) sin2 (75° - A) + cos2 (45° +A)
Use the given figure to find:
(i) tan θ°
(ii) θ°
(iii) sin2θ° - cos2θ°
(iv) Use sin θ° to find the value of x.
If A = B = 60°, verify that: cos(A - B) = cosA cosB + sinA sinB
In a right triangle ABC, right angled at C, if ∠B = 60° and AB = 15units, find the remaining angles and sides.
If ΔABC is a right triangle such that ∠C = 90°, ∠A = 45° and BC =7units, find ∠B, AB and AC.
In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB
If tan x° = `(5)/(12) . tan y° = (3)/(4)` and AB = 48m; find the length CD.
Evaluate the following: sin31° - cos59°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos72° - cos88°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
