Question

Point P is the centre of the circle and AB is a diameter. Find the coordinates of points B if coordinates of point A and P are (2, – 3) and (– 2, 0) respectively.

Given: A`square` and P`square`. Let B (x, y)

The centre of the circle is the midpoint of the diameter.

∴ Mid point formula,

`square = (square + x)/square`

⇒ `square = square` + x

⇒ x = `square - square`

⇒ x = – 6

and `square = (square + y)/2`

⇒ `square` + y = 0

⇒ y = 3

Hence coordinates of B is (– 6, 3).

Answer 1

Given: A(2, –3) and P(–2, 0). Let B (x, y)

The centre of the circle is the midpoint of the diameter.

∴ Mid point formula,

– 2 = `(bb2 + x)/bb2`

⇒ – 4 = 2 + x

⇒ x = – 4 – 2

⇒ x = – 6

and 0 = `(bb(-3) + y)/2`

⇒ – 3 + y = 0

⇒ y = 3

Hence coordinates of B is (– 6, 3).