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प्रश्न
One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be ______.
विकल्प
10x + 14y + 4 = 0
–10x – 14y + 4 = 0
–10x + 14y + 4 = 0
10x – 14y = –4
MCQ
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उत्तर
One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be 10x – 14y = –4.
Explanation:
Given equation of line is –5x + 7y – 2 = 0
Compare with a1x + b1y + c1 = 0
We get a1 = –5
b1 = 7
c1 = –2
Since condition for dependent linear equation is
`a_1/a_2 = b_1/b_2 = c_1/c_2 = 1/k`
∴ `5/a_2 = 7/b_2 = -2/c_2 = 1/k`
⇒ a2 = –5
b2 = 7k
c2 = –2k
Where, k is any arbitrary constant.
Substituting k = 2, then
a2 = –10
b2 = 14
And c2 = –4
∴ The required equation of line becomes – 10x + 14y – 4 = 0
⇒ 10x – 14y + 4 = 0
⇒ 10x – 14y = –4
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